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Thursday, 23 April 2015

Overriding







Overriding:
If a function is declared as virtual in the base class, it is virtual in all the derived classes. The redefinition of a virtual function in a derived class is usually called overriding.




Requirement :
Provide a menu to the user for the selection of shape and create the correspoding shape

#include "stdafx.h"
#include "conio.h"
#include <iostream>
using namespace std;

class Shape
{
public:
             void draw(){cout<<"Shape draw"<<endl;}
};
class Rectangle:public Shape
{
public:
            void draw(){cout<<"Rectangle draw"<<endl;}
};
class Circle:public Shape
{
public:
            void draw()
            {
            cout<<"Circle draw"<<endl;
            }
};

int _tmain(int argc, _TCHAR* argv[])
{
            int choice = 0;
            cout<<"enter 1 for rectangle ,2 for circle"<<endl;
            cin>>choice;
            if(choice == 1)
            {
                        Rectangle R;
                        R.draw();

            }
            else if(choice == 2)
            {
                        Circle C;
                        s.draw();
            }
            else
                        cout<<"wrong selection"<<endl;
            return 0;
}
In the above program,a menu is provided to the user and based on selection,the draw method is called using the corresponding object.

Requirement change:
Take all the inputs from the user once and print the dimensions of all shapes in the same order.

#include <vector>
#include <string>
#include <iostream>
using namespace std;

class Shape
{
public:
             void draw(){cout<<"Shape draw"<<endl;}
};
class Rectangle:public Shape
{
public:
            void draw(){cout<<"Rectangle draw"<<endl;}
};
class Circle:public Shape
{
public:
            void draw()
            {
            cout<<"Circle draw"<<endl;
            }
};

int _tmain(int argc, _TCHAR* argv[])
{
     vector<Shape *> shapelist;
            Shape *s;
            int choice = 1;
            cout<<"enter 1 for rectangle ,2 for circle,0 for exit"<<endl;
           

            while(choice>0)
            {
                        cin>>choice;
                        if(choice == 1)
                        {
                                    Rectangle R;
                                    s=&R;
                                    shapelist.push_back(s);
                        }
                        else if(choice == 2)
                        {
                                    Circle C;
                                    s=&C;
                                    shapelist.push_back(s);
                        }
                        else
                                    break;
            }
            for(int i =0;i<shapelist.size();i++)
            {
                        shapelist[i]->draw();
            }

            return 0;
}
In the above program,a call is made to the draw method using the upcasted pointer.If a call is made to a non-virtual member of a class which exists both in base and derived classes,the type of pointer decides the method to be called.In this case,in both the occasions,a call to the base class method is called.


To call methods of derived classes,add a keyword virtual in the base class.
- See more at: http://labstrikes.blogspot.in/2012/08/adsense-middle-blog-post.html#sthash.gQgSkqx8.dpuf

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